ftp_size

(PHP 4, PHP 5, PHP 7, PHP 8)

ftp_size — 返回指定文件的大小

说明

ftp_size(FTP\Connection $ftp, string $filename): int

ftp_size() 函数返回指定文件的大小（以字节为单位）。

注意:
不是所有服务器都支持该功能。

参数

ftp: FTP\Connection 实例。
filename: 远程文件。

返回值

成功时返回文件大小，错误返回 -1。

更新日志

版本	说明
8.1.0	现在 `ftp` 参数接受 FTP\Connection 实例，之前接受 resource。

示例

示例 #1 ftp_size() 示例

<?php

$file = 'somefile.txt';

// 简单基本连接
$ftp = ftp_connect($ftp_server);

// 使用用户名和密码进行登录
$login_result = ftp_login($ftp, $ftp_user_name, $ftp_user_pass);

// 获取 $file 文件大小
$res = ftp_size($ftp, $file);

if ($res != -1) {
    echo "size of $file is $res bytes";
} else {
    echo "couldn't get the size";
}

// 关闭连接
ftp_close($ftp);

?>

参见

ftp_rawlist() - 返回指定目录下文件的详细列表

改进此页面

了解如何改进此页面 • 提交拉取请求 • 报告一个错误

＋添加备注

用户贡献的备注 11 notes

down

gerben at gerbs dot net ¶

12 years ago

To overcome the 2 GB limitation, the ftp_raw solution below is probably the nicest. You can also perform this command using regular FTP commands:



<?php

$response =  ftp_raw($ftpConnection, "SIZE $filename");

$filesize = floatval(str_replace('213 ', '', $response[0]));

?>



[However, this] is insufficient for use on directories. As per RFC 3659 (http://tools.ietf.org/html/rfc3659#section-4.2), servers should return error 550 (File not found) if the command is issued on something else than a file, or if some other error occurred. For example, Filezilla indeed returns this string when using the ftp_raw command on a directory:



array(1) {

  [0]=>

  string(18) "550 File not found"

}



RFC 959 (http://tools.ietf.org/html/rfc959) dictates that the returned string always consists of exactly 3 digits, followed by 1 space, followed by some text. (Multi-line text is allowed, but I am ignoring that.) So it is probably better to split the string with substr, or even a regular expression.



<?php

$response = ftp_raw($ftp, "SIZE $filename");

$responseCode = substr($response[0], 0, 3);

$responseMessage = substr($response[0], 4);

?>



Or with a regular expression:



<?php

$response = ftp_raw($ftp, "SIZE $filename");

if (preg_match("/^(\\d{3}) (.*)$/", $response[0], $matches) == 0)

    throw new Exception("Unable to parse FTP reply: ".$response[0]);

list($response, $responseCode, $responseMessage) = $matches;

?>



You could then decide to assume that response code '550' means that it's a directory. I guess that's just as 'dangerous' as assuming that ftp_size -1 means that it's a directory.

down

project_t4 at hotmail dot com ¶

20 years ago

Just to let people out there know, on my windows 2000 server running Apache and php i was returned 0 not -1 for directories.

foreach ($dir_list as $item)
    {
      if(ftp_size($conn_id, $item) == "0")
      {
      echo "<br>Directory:: ".$item;
      } else {
      echo "<br>File:: ".$item;
      }
    }

This outputs a list of the remote directory and indicates which items are directories and which are files.

down

ibeono at gmail dot com ¶

13 years ago

If you experience troubles with size of large file then you can use ftp_rawlist function and parse it result

down

chuck at t8design dot com ¶

18 years ago

note that project_t4 at hotmail dot com's example above doesn't work in general, though it works on his Win2K/Apache server; as far as I can tell there is no way to check over ftp whether a directory exists.  This function's behavior given a directory name seems to be at least somewhat dependent on your OS, web server, or ftp server, I don't know which.

down

adams[AT]techweavers[DOT]net ¶

19 years ago

Well this function is nice but if you have files larger then 2.1Gb or 2.1 Billion Bytes you cannot get its size.

down

Anonymous ¶

20 years ago

To get a dirsize recursive you can use this simple function:

<?php # copyright by fackelkind | codeMaster
    function getRecDirSize ($connection, $dir){
        $temp = ftp_rawlist ($connection, "-alR $dir");
        foreach ($temp as $file){
            if (ereg ("([-d][rwxst-]+).* ([0-9]) ([a-zA-Z0-9]+).* ([a-zA-Z0-9]+).* ([0-9]*) ([a-zA-Z]+[0-9: ]*[0-9]) ([0-9]{2}:[0-9]{2}) (.+)", $file, $regs)){  
                $isdir = (substr ($regs[1],0,1) == "d");
                if (!$isdir)
                    $size += $regs[5];
            }
        }
        return $size;
    }
    $dirSize = getRecDirSize ($conID, "/");
?>

down

nicke_ at at_h9k dot com ¶

21 years ago

This will return the filesize on remote host and the size if you download it in FTP_BINARY mode. If you are using FTP_ASCII in ftp_get() the size can be changed.

down

victor59 at yahoo dot com dot hk ¶

21 years ago

$file= 'filename with space.txt';
$size = ftp_size($this->ftp, urldecode($file) );

this one can correctly return the size
otherwize, it always return -1

down

-1

miccots at gmail dot com ¶

17 years ago

2 adams[AT]techweavers[DOT]net:
To get a size of large file (f. ex.: 3.2 Gb) you have to format the result returned by ftp_size():

$size = sprintf ("%u", ftp_size($connection, $file_name));

So you can get the real size of big files. But this method is not good for checking is this a dir (when ftp_size() returns -1).

down

-1

C_Muller ¶

17 years ago

For checking if a certain folder exists try using ftp_nlist() function to get a directory list in array. By using in_array('foldername') you can find out if it is there or not.

down

-2

bluerain [at] telenet [dot] be ¶

15 years ago

To overcome the 2GB file size limit, you can open your own socket to get the file size of a large file. Quick and dirty script:



<?php

$socket=fsockopen($hostName, 21);

$t=fgets($socket, 128);

fwrite($socket, "USER $myLogin\r\n");

$t=fgets($socket, 128);

fwrite($socket, "PASS $myPass\r\n");

$t=fgets($socket, 128);

fwrite($socket, "SIZE $fileName\r\n");

$t=fgets($socket, 128);

$fileSize=floatval(str_replace("213 ","",$t));

echo $fileSize;

fwrite($socket, "QUIT\r\n");

fclose($socket);

?>