mysqli_result::fetch_assoc

    mysqli_fetch_assoc

    (PHP 5, PHP 7, PHP 8)

    mysqli_result::fetch_assoc -- mysqli_fetch_assoc — Fetch the next row of a result set as an associative array

    Опис

    Об'єктно-орієнтований стиль

    public mysqli_result::fetch_assoc(): array|null|false

    Процедурний стиль

    mysqli_fetch_assoc(mysqli_result $result): array|null|false

    Fetches one row of data from the result set and returns it as an associative array. Each subsequent call to this function will return the next row within the result set, or null if there are no more rows.

    If two or more columns of the result have the same name, the last column will take precedence and overwrite any previous data. To access multiple columns with the same name, mysqli_fetch_row() may be used to fetch the numerically indexed array, or aliases may be used in the SQL query select list to give columns different names.

    Зауваження: Ця функція є чутливою до регістру назв полів.

    Зауваження: Ця функція встановлює NULL-полям значення PHP null.

    Параметри

    result

    Тільки процедурний стиль: об'єкт mysqli_result, якого повертає одна з функцій mysqli_query(), mysqli_store_result(), mysqli_use_result() або mysqli_stmt_get_result().

    Значення, що повертаються

    Returns an associative array representing the fetched row, where each key in the array represents the name of one of the result set's columns, null if there are no more rows in the result set, або false в разі помилки.

    Приклади

    Приклад #1 mysqli_result::fetch_assoc() example

    Об'єктно-орієнтований стиль

    <?php

    mysqli_report    (MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
    $mysqli = new mysqli("localhost", "my_user", "my_password", "world");

    $query = "SELECT Name, CountryCode FROM City ORDER BY ID DESC";

    $result = $mysqli->query($query);

    /* fetch associative array */
    while ($row = $result->fetch_assoc()) {
    printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
    }

    Процедурний стиль

    <?php

    mysqli_report    (MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
    $mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");

    $query = "SELECT Name, CountryCode FROM City ORDER BY ID DESC";

    $result = mysqli_query($mysqli, $query);

    /* fetch associative array */
    while ($row = mysqli_fetch_assoc($result)) {
    printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
    }

    Подані вище приклади виведуть щось схоже на:

    Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

    Приклад #2 Comparison of mysqli_result iterator and mysqli_result::fetch_assoc() usage

    mysqli_result can be iterated using foreach. The result set will always be iterated from the first row, regardless of the current position.

    <?php

    mysqli_report    (MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
    $mysqli = new mysqli("localhost", "my_user", "my_password", "world");

    $query = 'SELECT Name, CountryCode FROM City ORDER BY ID DESC';

    // Using iterators
    $result = $mysqli->query($query);
    foreach (    $result as $row) {
    printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
    }

    echo     "\n==================\n";

    // Not using iterators
    $result = $mysqli->query($query);
    while (    $row = $result->fetch_assoc()) {
    printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
    }

    Поданий вище приклад виведе щось схоже на:

    Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

==================
Pueblo (USA)
Arvada (USA)
Cape Coral (USA)
Green Bay (USA)
Santa Clara (USA)

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    User Contributed Notes 3 notes

    up
    87
    Miller
    11 years ago
    I often like to have my results sent elsewhere in the format of an array (although keep in mind that if you just plan on traversing through the array in another part of the script, this extra step is just a waste of time).

    This is my one-liner for transforming a mysqli_result set into an array.
    <?php
    $sql     = new MySQLi($host, $username, $password, $database);

    $result = $sql->query("SELECT * FROM `$table`;");
    for (    $set = array (); $row = $result->fetch_assoc(); $set[] = $row);
    print_r($set);
    ?>

    Outputs:
    Array
    (
    [0] => Array
    (
    [id] => 1
    [field2] => a
    [field3] => b
    ),
    [1] => Array
    (
    [id] => 2
    [field2] => c
    [field3] => d
    )
    )

    I use other variations to adapt to the situation, i.e. if I am selecting only one field:
    <?php
    $sql     = new MySQLi($host, $username, $password, $database);
    $result = $sql->query("SELECT `field2` FROM `$table`;");
    for (    $set = array (); $row = $result->fetch_assoc(); $set[] = $row['field2']);
    print_r($set);
    ?>
    Outputs:
    Array
    (
    [0] => a
    [1] => c
    )

    Or, to make the array associative with the primary index (code assumes primary index is the first field in the table):
    <?php
    $sql     = new MySQLi($host, $username, $password, $database);
    $result = $sql->query("SELECT * FROM `$table`;");
    for (    $set = array (); $row = $result->fetch_assoc(); $set[array_shift($row)] = $row);
    print_r($set);
    ?>
    Outputs:
    Array
    (
    [1] => Array
    (
    [field2] => a
    [field3] => b
    ),
    [2] => Array
    (
    [field2] => c
    [field3] => d
    )
    )
    up
    28
    james dot phx at gmail dot com
    13 years ago
    IMPORTANT NOTE:

    If you were used to using code like this:

    <?php
    while(false !== ($row = mysql_fetch_assoc($result)))
    {
    //...
    }
    ?>

    You must change it to this for mysqli:

    <?php
    while(null !== ($row = mysqli_fetch_assoc($result)))
    {
    //...
    }
    ?>

    The former will cause your script to run until max_execution_time is reached.
    up
    1
    Enrique Garcia
    1 year ago
    There is a difference between MariaDB and MySQL(>5.4) whether the input parameter (mysqli object) has data or is empty (it comes from a previus query).
    -MariaDB: you get an exception:
    Fatal error: Uncaught TypeError: mysqli_fetch_assoc(): Argument #1 ($result) must be of type mysqli_result
    -MySQL: you can continue, in spite of not having data in the mysqli object.
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